What are the solutions to the equation solvefor x,x^2-4x+2=0 ?

The solutions to the equation solvefor x,x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)

Find the zeros of solvefor x,x^2-4x+2=0

The zeros of solvefor x,x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)

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x, x^{2} - 4 x + 2 = 0

x = 2 + 2, x = 2 - 2

Solution steps

x^{2} - 4 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 2 = 22

x_{1, 2} = \frac{- ( - 4 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 2}{2 \cdot 1} : 2 + 2

x = \frac{- ( - 4 ) - 2 2}{2 \cdot 1} : 2 - 2

The solutions to the quadratic equation are:

x = 2 + 2, x = 2 - 2

4 x^{2} + 48 = 0

k^{2} + k - 2 = 0

4000 (1 + r)^{2} + 1000 (1 + r) = 5941.23

t^{2} - 4 t - 5 = 0

21 - 3 x^{2} = 0

What are the solutions to the equation solvefor x,x^2-4x+2=0 ?
The solutions to the equation solvefor x,x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)
Find the zeros of solvefor x,x^2-4x+2=0
The zeros of solvefor x,x^2-4x+2=0 are x=2+sqrt(2),x=2-sqrt(2)