What are the solutions to the equation k^2+k-2=0 ?

The solutions to the equation k^2+k-2=0 are k=1,k=-2

Find the zeros of k^2+k-2=0

The zeros of k^2+k-2=0 are k=1,k=-2

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k^{2} + k - 2 = 0

k = 1, k = - 2

Solution steps

k^{2} + k - 2 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

k_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- 1 + 3}{2 \cdot 1}, k_{2} = \frac{- 1 - 3}{2 \cdot 1}

k = \frac{- 1 + 3}{2 \cdot 1} : 1

k = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

k = 1, k = - 2

4000 (1 + r)^{2} + 1000 (1 + r) = 5941.23

t^{2} - 4 t - 5 = 0

21 - 3 x^{2} = 0

2 x^{2} - 8 x - 10 = x + 8

4 x^{2} - 16 x + 17

What are the solutions to the equation k^2+k-2=0 ?
The solutions to the equation k^2+k-2=0 are k=1,k=-2
Find the zeros of k^2+k-2=0
The zeros of k^2+k-2=0 are k=1,k=-2