What are the solutions to the equation 2x^2-8x-10=x+8 ?

The solutions to the equation 2x^2-8x-10=x+8 are x=6,x=-3/2

Find the zeros of 2x^2-8x-10=x+8

The zeros of 2x^2-8x-10=x+8 are x=6,x=-3/2

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2 x^{2} - 8 x - 10 = x + 8

x = 6, x = - \frac{3}{2}

Decimal Notation

x = 6, x = - 1.5

Solution steps

2 x^{2} - 8 x - 10 = x + 8

Move

8

to the left side

2 x^{2} - 8 x - 18 = x

Move

x

to the left side

2 x^{2} - 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 ( - 18 )}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 (- 18) = 15

x_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 2}

x = \frac{- ( - 9 ) + 15}{2 \cdot 2} : 6

x = \frac{- ( - 9 ) - 15}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 6, x = - \frac{3}{2}

4 x^{2} - 16 x + 17

y, 5 x^{2} - 2 x y + 2 y^{2} - 2 y - 71 = 0

- 2 x^{2} + 6 x - 1 = 0

8 x^{2} - 9 x + 1 = 0

x (- 1 + x) = 0

What are the solutions to the equation 2x^2-8x-10=x+8 ?
The solutions to the equation 2x^2-8x-10=x+8 are x=6,x=-3/2
Find the zeros of 2x^2-8x-10=x+8
The zeros of 2x^2-8x-10=x+8 are x=6,x=-3/2