What are the solutions to the equation -2x^2+6x-1=0 ?

The solutions to the equation -2x^2+6x-1=0 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2

Find the zeros of -2x^2+6x-1=0

The zeros of -2x^2+6x-1=0 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2

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- 2 x^{2} + 6 x - 1 = 0

x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

Solution steps

- 2 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

6^{2} - 4 (- 2) (- 1) = 27

x_{1, 2} = \frac{- 6 \pm 2 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 7}{2 ( - 2 )}, x_{2} = \frac{- 6 - 2 7}{2 ( - 2 )}

x = \frac{- 6 + 2 7}{2 ( - 2 )} : \frac{3 - 7}{2}

x = \frac{- 6 - 2 7}{2 ( - 2 )} : \frac{3 + 7}{2}

The solutions to the quadratic equation are:

x = \frac{3 - 7}{2}, x = \frac{3 + 7}{2}

8 x^{2} - 9 x + 1 = 0

x (- 1 + x) = 0

- 4.9 t^{2} + 31 t = 0

x^{2} - 11 x - 28 = 0

- 2 x^{2} + 6 x - 5 = 0

What are the solutions to the equation -2x^2+6x-1=0 ?
The solutions to the equation -2x^2+6x-1=0 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2
Find the zeros of -2x^2+6x-1=0
The zeros of -2x^2+6x-1=0 are x=(3-sqrt(7))/2 ,x=(3+sqrt(7))/2