What are the solutions to the equation x^2-11x-28=0 ?

The solutions to the equation x^2-11x-28=0 are x=(11+sqrt(233))/2 ,x=(11-sqrt(233))/2

Find the zeros of x^2-11x-28=0

The zeros of x^2-11x-28=0 are x=(11+sqrt(233))/2 ,x=(11-sqrt(233))/2

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x^{2} - 11 x - 28 = 0

x = \frac{11 + 233}{2}, x = \frac{11 - 233}{2}

Decimal Notation

x = 13.13216 \dots, x = - 2.13216 \dots

Solution steps

x^{2} - 11 x - 28 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot (- 28) = 233

x_{1, 2} = \frac{- ( - 11 ) \pm 233}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 233}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 233}{2 \cdot 1}

x = \frac{- ( - 11 ) + 233}{2 \cdot 1} : \frac{11 + 233}{2}

x = \frac{- ( - 11 ) - 233}{2 \cdot 1} : \frac{11 - 233}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 233}{2}, x = \frac{11 - 233}{2}

- 2 x^{2} + 6 x - 5 = 0

x^{2} + 2 x = - 13

3 s^{2} - 2 s = - 5

(x - 2) (x - 7) = 0

0 = 4 x - x^{2}

What are the solutions to the equation x^2-11x-28=0 ?
The solutions to the equation x^2-11x-28=0 are x=(11+sqrt(233))/2 ,x=(11-sqrt(233))/2
Find the zeros of x^2-11x-28=0
The zeros of x^2-11x-28=0 are x=(11+sqrt(233))/2 ,x=(11-sqrt(233))/2