What are the solutions to the equation 3s^2-2s=-5 ?

The solutions to the equation 3s^2-2s=-5 are s= 1/3+i(sqrt(14))/3 ,s= 1/3-i(sqrt(14))/3

Find the zeros of 3s^2-2s=-5

The zeros of 3s^2-2s=-5 are s= 1/3+i(sqrt(14))/3 ,s= 1/3-i(sqrt(14))/3

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3 s^{2} - 2 s = - 5

s = \frac{1}{3} + i \frac{14}{3}, s = \frac{1}{3} - i \frac{14}{3}

Solution steps

3 s^{2} - 2 s = - 5

Move

5

to the left side

3 s^{2} - 2 s + 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

Simplify

(- 2)^{2} - 4 \cdot 3 \cdot 5 : 214 i

s_{1, 2} = \frac{- ( - 2 ) \pm 2 14 i}{2 \cdot 3}

Separate the solutions

s_{1} = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 3}, s_{2} = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 3}

s = \frac{- ( - 2 ) + 2 14 i}{2 \cdot 3} : \frac{1}{3} + i \frac{14}{3}

s = \frac{- ( - 2 ) - 2 14 i}{2 \cdot 3} : \frac{1}{3} - i \frac{14}{3}

The solutions to the quadratic equation are:

s = \frac{1}{3} + i \frac{14}{3}, s = \frac{1}{3} - i \frac{14}{3}

(x - 2) (x - 7) = 0

0 = 4 x - x^{2}

12 x^{2} + 48 x + 36 = 0

a^{2} + 8 a + 16 = 0

6 x^{2} + 6 x - 6 = 0

What are the solutions to the equation 3s^2-2s=-5 ?
The solutions to the equation 3s^2-2s=-5 are s= 1/3+i(sqrt(14))/3 ,s= 1/3-i(sqrt(14))/3
Find the zeros of 3s^2-2s=-5
The zeros of 3s^2-2s=-5 are s= 1/3+i(sqrt(14))/3 ,s= 1/3-i(sqrt(14))/3