What are the solutions to the equation 6x^2+6x-6=0 ?

The solutions to the equation 6x^2+6x-6=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2

Find the zeros of 6x^2+6x-6=0

The zeros of 6x^2+6x-6=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2

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6 x^{2} + 6 x - 6 = 0

x = \frac{- 1 + 5}{2}, x = - \frac{1 + 5}{2}

Solution steps

6 x^{2} + 6 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 6 ( - 6 )}{2 \cdot 6}

6^{2} - 4 \cdot 6 (- 6) = 65

x_{1, 2} = \frac{- 6 \pm 6 5}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 6 + 6 5}{2 \cdot 6}, x_{2} = \frac{- 6 - 6 5}{2 \cdot 6}

x = \frac{- 6 + 6 5}{2 \cdot 6} : \frac{- 1 + 5}{2}

x = \frac{- 6 - 6 5}{2 \cdot 6} : - \frac{1 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 5}{2}, x = - \frac{1 + 5}{2}

3 x^{2} + 5 x - 68 = 0

(x - 2) (x - 5) = 6

x^{2} - 5 x + 6

- 4 x^{2} + 8 x - 3 = 0

(4 x - 5)^{2} = 25

What are the solutions to the equation 6x^2+6x-6=0 ?
The solutions to the equation 6x^2+6x-6=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2
Find the zeros of 6x^2+6x-6=0
The zeros of 6x^2+6x-6=0 are x=(-1+sqrt(5))/2 ,x=-(1+sqrt(5))/2