What are the solutions to the equation 1^2+3^2=x^2 ?

The solutions to the equation 1^2+3^2=x^2 are x=sqrt(10),x=-sqrt(10)

Find the zeros of 1^2+3^2=x^2

The zeros of 1^2+3^2=x^2 are x=sqrt(10),x=-sqrt(10)

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1^{2} + 3^{2} = x^{2}

x = 10, x = - 10

Decimal Notation

x = 3.16227 \dots, x = - 3.16227 \dots

Solution steps

1^{2} + 3^{2} = x^{2}

Switch sides

x^{2} = 1^{2} + 3^{2}

Simplify

1^{2} + 3^{2} : 10

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 10, x = - 10

4 x^{2} - 15 x = 0

12 x^{2} - 112 x + 180 = 0

\frac{x ^{2}}{8} = \frac{1}{2}

x^{2} + 15 x - 2 = 0

(x + 8)^{2} = 4

What are the solutions to the equation 1^2+3^2=x^2 ?
The solutions to the equation 1^2+3^2=x^2 are x=sqrt(10),x=-sqrt(10)
Find the zeros of 1^2+3^2=x^2
The zeros of 1^2+3^2=x^2 are x=sqrt(10),x=-sqrt(10)