What are the solutions to the equation x^2-4x+4=75 ?

The solutions to the equation x^2-4x+4=75 are x=2+5sqrt(3),x=2-5sqrt(3)

Find the zeros of x^2-4x+4=75

The zeros of x^2-4x+4=75 are x=2+5sqrt(3),x=2-5sqrt(3)

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x^{2} - 4 x + 4 = 75

x = 2 + 53, x = 2 - 53

Solution steps

x^{2} - 4 x + 4 = 75

Move

75

to the left side

x^{2} - 4 x - 71 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 71 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 71) = 103

x_{1, 2} = \frac{- ( - 4 ) \pm 10 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 10 3}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 10 3}{2 \cdot 1}

x = \frac{- ( - 4 ) + 10 3}{2 \cdot 1} : 2 + 53

x = \frac{- ( - 4 ) - 10 3}{2 \cdot 1} : 2 - 53

The solutions to the quadratic equation are:

x = 2 + 53, x = 2 - 53

4 x^{2} + 8 x - 32 = 0

9 x^{2} - 5 x - 7 = 0

(x + 8)^{2} - 4 = - 20

x^{2} - \frac{9}{16} = 0

1200 - 1.5 x^{2} = 200 + x^{2}

What are the solutions to the equation x^2-4x+4=75 ?
The solutions to the equation x^2-4x+4=75 are x=2+5sqrt(3),x=2-5sqrt(3)
Find the zeros of x^2-4x+4=75
The zeros of x^2-4x+4=75 are x=2+5sqrt(3),x=2-5sqrt(3)