What are the solutions to the equation y^2-2y=8 ?

The solutions to the equation y^2-2y=8 are y=4,y=-2

Find the zeros of y^2-2y=8

The zeros of y^2-2y=8 are y=4,y=-2

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y^{2} - 2 y = 8

y = 4, y = - 2

Solution steps

y^{2} - 2 y = 8

Move

8

to the left side

y^{2} - 2 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 8) = 6

y_{1, 2} = \frac{- ( - 2 ) \pm 6}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 2 ) + 6}{2 \cdot 1}, y_{2} = \frac{- ( - 2 ) - 6}{2 \cdot 1}

y = \frac{- ( - 2 ) + 6}{2 \cdot 1} : 4

y = \frac{- ( - 2 ) - 6}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

y = 4, y = - 2

2 x^{2} + 20 x + 48 = 0

x^{2} - 10 = - 18

18 x^{2} - 72 = 0

x^{2} - 3 + 2 = 0

- x^{2} + 2 x - 7 = 0

What are the solutions to the equation y^2-2y=8 ?
The solutions to the equation y^2-2y=8 are y=4,y=-2
Find the zeros of y^2-2y=8
The zeros of y^2-2y=8 are y=4,y=-2