What are the solutions to the equation -x^2+2x-7=0 ?

The solutions to the equation -x^2+2x-7=0 are x=1-sqrt(6)i,x=1+sqrt(6)i

Find the zeros of -x^2+2x-7=0

The zeros of -x^2+2x-7=0 are x=1-sqrt(6)i,x=1+sqrt(6)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 2 x - 7 = 0

x = 1 - 6 i, x = 1 + 6 i

Solution steps

- x^{2} + 2 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

Simplify

2^{2} - 4 (- 1) (- 7) : 26 i

x_{1, 2} = \frac{- 2 \pm 2 6 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 6 i}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 6 i}{2 ( - 1 )}

x = \frac{- 2 + 2 6 i}{2 ( - 1 )} : 1 - 6 i

x = \frac{- 2 - 2 6 i}{2 ( - 1 )} : 1 + 6 i

The solutions to the quadratic equation are:

x = 1 - 6 i, x = 1 + 6 i

x^{2} = 2 x^{2}

4 x (x + 6) = - 40

- 4 x^{2} + 5 x - 1 = 0

x^{2} - 16 x + 64 = 0

x^{2} + 10 x - 30 = 0

What are the solutions to the equation -x^2+2x-7=0 ?
The solutions to the equation -x^2+2x-7=0 are x=1-sqrt(6)i,x=1+sqrt(6)i
Find the zeros of -x^2+2x-7=0
The zeros of -x^2+2x-7=0 are x=1-sqrt(6)i,x=1+sqrt(6)i