What are the solutions to the equation 4x(x+6)=-40 ?

The solutions to the equation 4x(x+6)=-40 are x=-3+i,x=-3-i

Find the zeros of 4x(x+6)=-40

The zeros of 4x(x+6)=-40 are x=-3+i,x=-3-i

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4 x (x + 6) = - 40

x = - 3 + i, x = - 3 - i

Solution steps

4 x (x + 6) = - 40

Expand

4 x (x + 6) : 4 x^{2} + 24 x

4 x^{2} + 24 x = - 40

Move

40

to the left side

4 x^{2} + 24 x + 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 40}{2 \cdot 4}

Simplify

2 4^{2} - 4 \cdot 4 \cdot 40 : 8 i

x_{1, 2} = \frac{- 24 \pm 8 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 8 i}{2 \cdot 4}, x_{2} = \frac{- 24 - 8 i}{2 \cdot 4}

x = \frac{- 24 + 8 i}{2 \cdot 4} : - 3 + i

x = \frac{- 24 - 8 i}{2 \cdot 4} : - 3 - i

The solutions to the quadratic equation are:

x = - 3 + i, x = - 3 - i

- 4 x^{2} + 5 x - 1 = 0

x^{2} - 16 x + 64 = 0

x^{2} + 10 x - 30 = 0

y, m = y^{2} - \frac{y ^{1}}{x ^{2}} - x^{1}

x, z^{2} + 4 y^{2} - 4 x^{2} = 0

What are the solutions to the equation 4x(x+6)=-40 ?
The solutions to the equation 4x(x+6)=-40 are x=-3+i,x=-3-i
Find the zeros of 4x(x+6)=-40
The zeros of 4x(x+6)=-40 are x=-3+i,x=-3-i