What are the solutions to the equation solvefor x,x^2-2xy+y^2-1=0 ?

The solutions to the equation solvefor x,x^2-2xy+y^2-1=0 are x=y+1,x=y-1

Find the zeros of solvefor x,x^2-2xy+y^2-1=0

The zeros of solvefor x,x^2-2xy+y^2-1=0 are x=y+1,x=y-1

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solve for

x, x^{2} - 2 x y + y^{2} - 1 = 0

x = y + 1, x = y - 1

Solution steps

x^{2} - 2 x y + y^{2} - 1 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 y x + y^{2} - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 y ) \pm ( - 2 y ) ^{2} - 4 \cdot 1 \cdot ( y ^{2} - 1 )}{2 \cdot 1}

(- 2 y)^{2} - 4 \cdot 1 \cdot (y^{2} - 1) = 2

x_{1, 2} = \frac{- ( - 2 y ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 y ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 2 y ) - 2}{2 \cdot 1}

x = \frac{- ( - 2 y ) + 2}{2 \cdot 1} : y + 1

x = \frac{- ( - 2 y ) - 2}{2 \cdot 1} : y - 1

The solutions to the quadratic equation are:

x = y + 1, x = y - 1

x^{2} + 21 x = 11 - x^{2}

4 x^{2} - 64 = 8 x - 4

x^{2} - 8 x + 1

8 x^{2} - 14 x + 5 = 0

- 2 x^{2} - 12 x - 9 = 0

What are the solutions to the equation solvefor x,x^2-2xy+y^2-1=0 ?
The solutions to the equation solvefor x,x^2-2xy+y^2-1=0 are x=y+1,x=y-1
Find the zeros of solvefor x,x^2-2xy+y^2-1=0
The zeros of solvefor x,x^2-2xy+y^2-1=0 are x=y+1,x=y-1