What are the solutions to the equation -x^2+14x+94=0 ?

The solutions to the equation -x^2+14x+94=0 are x=7-sqrt(143),x=7+sqrt(143)

Find the zeros of -x^2+14x+94=0

The zeros of -x^2+14x+94=0 are x=7-sqrt(143),x=7+sqrt(143)

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- x^{2} + 14 x + 94 = 0

x = 7 - 143, x = 7 + 143

Decimal Notation

x = - 4.95826 \dots, x = 18.95826 \dots

Solution steps

- x^{2} + 14 x + 94 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 1 ) \cdot 94}{2 ( - 1 )}

1 4^{2} - 4 (- 1) \cdot 94 = 2143

x_{1, 2} = \frac{- 14 \pm 2 143}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 14 + 2 143}{2 ( - 1 )}, x_{2} = \frac{- 14 - 2 143}{2 ( - 1 )}

x = \frac{- 14 + 2 143}{2 ( - 1 )} : 7 - 143

x = \frac{- 14 - 2 143}{2 ( - 1 )} : 7 + 143

The solutions to the quadratic equation are:

x = 7 - 143, x = 7 + 143

x^{2} + 7 x - 18 = 0

- 4 x^{2} + x - 1 = 0

8 x^{2} - 20 x = 0

- \frac{23}{40} x^{2} + \frac{1}{2} x + 10 = 0

8 z^{2} - 9 z + 16 = 0

What are the solutions to the equation -x^2+14x+94=0 ?
The solutions to the equation -x^2+14x+94=0 are x=7-sqrt(143),x=7+sqrt(143)
Find the zeros of -x^2+14x+94=0
The zeros of -x^2+14x+94=0 are x=7-sqrt(143),x=7+sqrt(143)