What are the solutions to the equation solvefor x,y=x^2-9x+20 ?

The solutions to the equation solvefor x,y=x^2-9x+20 are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2

Find the zeros of solvefor x,y=x^2-9x+20

The zeros of solvefor x,y=x^2-9x+20 are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2

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solve for

x, y = x^{2} - 9 x + 20

x = \frac{9 + 4 y + 1}{2}, x = \frac{9 - 4 y + 1}{2}

Solution steps

y = x^{2} - 9 x + 20

Switch sides

x^{2} - 9 x + 20 = y

Move

y

to the left side

x^{2} - 9 x + 20 - y = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot ( 20 - y )}{2 \cdot 1}

Simplify

(- 9)^{2} - 4 \cdot 1 \cdot (20 - y) : 4 y + 1

x_{1, 2} = \frac{- ( - 9 ) \pm 4 y + 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 4 y + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 4 y + 1}{2 \cdot 1}

x = \frac{- ( - 9 ) + 4 y + 1}{2 \cdot 1} : \frac{9 + 4 y + 1}{2}

x = \frac{- ( - 9 ) - 4 y + 1}{2 \cdot 1} : \frac{9 - 4 y + 1}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 4 y + 1}{2}, x = \frac{9 - 4 y + 1}{2}

x^{2} + 3

(5 k - 3) (2 k + 1) = 4, 6 - k (5 k - 3) (2 k + 1) = 46 - k

2 1^{2} + 2 8^{2} = c^{2}

0 = 48 x + 8 x^{2}

x^{2} + 2 (1)^{2} - 2 (1) - 5 = 16

What are the solutions to the equation solvefor x,y=x^2-9x+20 ?
The solutions to the equation solvefor x,y=x^2-9x+20 are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2
Find the zeros of solvefor x,y=x^2-9x+20
The zeros of solvefor x,y=x^2-9x+20 are x=(9+sqrt(4y+1))/2 ,x=(9-sqrt(4y+1))/2