What are the solutions to the equation 0=48x+8x^2 ?

The solutions to the equation 0=48x+8x^2 are x=0,x=-6

Find the zeros of 0=48x+8x^2

The zeros of 0=48x+8x^2 are x=0,x=-6

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0 = 48 x + 8 x^{2}

x = 0, x = - 6

Solution steps

0 = 48 x + 8 x^{2}

Switch sides

48 x + 8 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} + 48 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

4 8^{2} - 4 \cdot 8 \cdot 0 = 48

x_{1, 2} = \frac{- 48 \pm 48}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 48 + 48}{2 \cdot 8}, x_{2} = \frac{- 48 - 48}{2 \cdot 8}

x = \frac{- 48 + 48}{2 \cdot 8} : 0

x = \frac{- 48 - 48}{2 \cdot 8} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

x^{2} + 2 (1)^{2} - 2 (1) - 5 = 16

x^{2} - 6 x - 4 = 0

a^{2} + 1 = 3 a - 1

3 + 9 r^{2} = 12

s^{2} + 7 s + 1 = 0

What are the solutions to the equation 0=48x+8x^2 ?
The solutions to the equation 0=48x+8x^2 are x=0,x=-6
Find the zeros of 0=48x+8x^2
The zeros of 0=48x+8x^2 are x=0,x=-6