What are the solutions to the equation x^2+12x-6=5 ?

The solutions to the equation x^2+12x-6=5 are x=-6+sqrt(47),x=-6-sqrt(47)

Find the zeros of x^2+12x-6=5

The zeros of x^2+12x-6=5 are x=-6+sqrt(47),x=-6-sqrt(47)

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x^{2} + 12 x - 6 = 5

x = - 6 + 47, x = - 6 - 47

Decimal Notation

x = 0.85565 \dots, x = - 12.85565 \dots

Solution steps

x^{2} + 12 x - 6 = 5

Move

5

to the left side

x^{2} + 12 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 11) = 247

x_{1, 2} = \frac{- 12 \pm 2 47}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 2 47}{2 \cdot 1}, x_{2} = \frac{- 12 - 2 47}{2 \cdot 1}

x = \frac{- 12 + 2 47}{2 \cdot 1} : - 6 + 47

x = \frac{- 12 - 2 47}{2 \cdot 1} : - 6 - 47

The solutions to the quadratic equation are:

x = - 6 + 47, x = - 6 - 47

x (6 + x) - 2 (x + 1) - 5 x = 4

(x + 9)^{2} = 16

y, 36 x^{2} + 25 y^{2} = 900

x^{2} - 2 x - 35 = 0

13 + 8 x = - 2 x^{2}

What are the solutions to the equation x^2+12x-6=5 ?
The solutions to the equation x^2+12x-6=5 are x=-6+sqrt(47),x=-6-sqrt(47)
Find the zeros of x^2+12x-6=5
The zeros of x^2+12x-6=5 are x=-6+sqrt(47),x=-6-sqrt(47)