What are the solutions to the equation x(6+x)-2(x+1)-5x=4 ?

The solutions to the equation x(6+x)-2(x+1)-5x=4 are x=3,x=-2

Find the zeros of x(6+x)-2(x+1)-5x=4

The zeros of x(6+x)-2(x+1)-5x=4 are x=3,x=-2

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x (6 + x) - 2 (x + 1) - 5 x = 4

x = 3, x = - 2

Solution steps

x (6 + x) - 2 (x + 1) - 5 x = 4

Expand

x (6 + x) - 2 (x + 1) - 5 x : x^{2} - x - 2

x^{2} - x - 2 = 4

Move

4

to the left side

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

(x + 9)^{2} = 16

y, 36 x^{2} + 25 y^{2} = 900

x^{2} - 2 x - 35 = 0

13 + 8 x = - 2 x^{2}

x^{2} + 2 b x - a^{2} + b^{2} = 0

What are the solutions to the equation x(6+x)-2(x+1)-5x=4 ?
The solutions to the equation x(6+x)-2(x+1)-5x=4 are x=3,x=-2
Find the zeros of x(6+x)-2(x+1)-5x=4
The zeros of x(6+x)-2(x+1)-5x=4 are x=3,x=-2