What are the solutions to the equation x^2+2bx-a^2+b^2=0 ?

The solutions to the equation x^2+2bx-a^2+b^2=0 are x=-b+a,x=-b-a

Find the zeros of x^2+2bx-a^2+b^2=0

The zeros of x^2+2bx-a^2+b^2=0 are x=-b+a,x=-b-a

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x^{2} + 2 b x - a^{2} + b^{2} = 0

x = - b + a, x = - b - a

Solution steps

x^{2} + 2 b x - a^{2} + b^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 b \pm ( 2 b ) ^{2} - 4 \cdot 1 \cdot ( - a ^{2} + b ^{2} )}{2 \cdot 1}

Simplify

(2 b)^{2} - 4 \cdot 1 \cdot (- a^{2} + b^{2}) : 2 a

x_{1, 2} = \frac{- 2 b \pm 2 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 b + 2 a}{2 \cdot 1}, x_{2} = \frac{- 2 b - 2 a}{2 \cdot 1}

x = \frac{- 2 b + 2 a}{2 \cdot 1} : - b + a

x = \frac{- 2 b - 2 a}{2 \cdot 1} : - b - a

The solutions to the quadratic equation are:

x = - b + a, x = - b - a

x^{2} - 18 = - 3 x

25 x^{2} = 100

x + x^{2} = 30

x^{2} - 20 x + 95 = 0

x^{2} + 23 x - 19 = 9 x - 4

What are the solutions to the equation x^2+2bx-a^2+b^2=0 ?
The solutions to the equation x^2+2bx-a^2+b^2=0 are x=-b+a,x=-b-a
Find the zeros of x^2+2bx-a^2+b^2=0
The zeros of x^2+2bx-a^2+b^2=0 are x=-b+a,x=-b-a