What are the solutions to the equation x^2+23x-19=9x-4 ?

The solutions to the equation x^2+23x-19=9x-4 are x=1,x=-15

Find the zeros of x^2+23x-19=9x-4

The zeros of x^2+23x-19=9x-4 are x=1,x=-15

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x^{2} + 23 x - 19 = 9 x - 4

x = 1, x = - 15

Solution steps

x^{2} + 23 x - 19 = 9 x - 4

Move

4

to the left side

x^{2} + 23 x - 15 = 9 x

Move

9 x

to the left side

x^{2} + 14 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

1 4^{2} - 4 \cdot 1 \cdot (- 15) = 16

x_{1, 2} = \frac{- 14 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 14 + 16}{2 \cdot 1}, x_{2} = \frac{- 14 - 16}{2 \cdot 1}

x = \frac{- 14 + 16}{2 \cdot 1} : 1

x = \frac{- 14 - 16}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 1, x = - 15

2 m^{2} + 5 m - 3 = 0

x, 2 x^{2} + 2 y^{2} - 8 x - 28 y + 106 = 0

5 x^{2} - 4 x = 1

\frac{( x + 2 ) ^{2}}{5} - \frac{( x ^{2} - 9 )}{4} = \frac{( x + 3 ) ^{2}}{2} + \frac{1}{5}

x, 4 x^{2} - 6 x y - 4 y^{2} = 15

What are the solutions to the equation x^2+23x-19=9x-4 ?
The solutions to the equation x^2+23x-19=9x-4 are x=1,x=-15
Find the zeros of x^2+23x-19=9x-4
The zeros of x^2+23x-19=9x-4 are x=1,x=-15