What are the solutions to the equation 2m^2+5m-3=0 ?

The solutions to the equation 2m^2+5m-3=0 are m= 1/2 ,m=-3

Find the zeros of 2m^2+5m-3=0

The zeros of 2m^2+5m-3=0 are m= 1/2 ,m=-3

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2 m^{2} + 5 m - 3 = 0

m = \frac{1}{2}, m = - 3

Solution steps

2 m^{2} + 5 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

m_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- 5 + 7}{2 \cdot 2}, m_{2} = \frac{- 5 - 7}{2 \cdot 2}

m = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

m = \frac{- 5 - 7}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

m = \frac{1}{2}, m = - 3

x, 2 x^{2} + 2 y^{2} - 8 x - 28 y + 106 = 0

5 x^{2} - 4 x = 1

\frac{( x + 2 ) ^{2}}{5} - \frac{( x ^{2} - 9 )}{4} = \frac{( x + 3 ) ^{2}}{2} + \frac{1}{5}

x, 4 x^{2} - 6 x y - 4 y^{2} = 15

w^{2} + w - 2 = 0

What are the solutions to the equation 2m^2+5m-3=0 ?
The solutions to the equation 2m^2+5m-3=0 are m= 1/2 ,m=-3
Find the zeros of 2m^2+5m-3=0
The zeros of 2m^2+5m-3=0 are m= 1/2 ,m=-3