What are the solutions to the equation w^2+w-2=0 ?

The solutions to the equation w^2+w-2=0 are w=1,w=-2

Find the zeros of w^2+w-2=0

The zeros of w^2+w-2=0 are w=1,w=-2

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w^{2} + w - 2 = 0

w = 1, w = - 2

Solution steps

w^{2} + w - 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

w_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 1 + 3}{2 \cdot 1}, w_{2} = \frac{- 1 - 3}{2 \cdot 1}

w = \frac{- 1 + 3}{2 \cdot 1} : 1

w = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

w = 1, w = - 2

x^{2} + x - 30 = 0

3 x^{2} - 60 = 3 x

3 x^{2} + 12 = 7 x + 32

5 p^{2} - 37 p = - 42

m^{2} - 8 m + 20 = 0

What are the solutions to the equation w^2+w-2=0 ?
The solutions to the equation w^2+w-2=0 are w=1,w=-2
Find the zeros of w^2+w-2=0
The zeros of w^2+w-2=0 are w=1,w=-2