What are the solutions to the equation 5p^2-37p=-42 ?

The solutions to the equation 5p^2-37p=-42 are p=6,p= 7/5

Find the zeros of 5p^2-37p=-42

The zeros of 5p^2-37p=-42 are p=6,p= 7/5

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5 p^{2} - 37 p = - 42

p = 6, p = \frac{7}{5}

Solution steps

5 p^{2} - 37 p = - 42

Move

42

to the left side

5 p^{2} - 37 p + 42 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 37 ) \pm ( - 37 ) ^{2} - 4 \cdot 5 \cdot 42}{2 \cdot 5}

(- 37)^{2} - 4 \cdot 5 \cdot 42 = 23

p_{1, 2} = \frac{- ( - 37 ) \pm 23}{2 \cdot 5}

Separate the solutions

p_{1} = \frac{- ( - 37 ) + 23}{2 \cdot 5}, p_{2} = \frac{- ( - 37 ) - 23}{2 \cdot 5}

p = \frac{- ( - 37 ) + 23}{2 \cdot 5} : 6

p = \frac{- ( - 37 ) - 23}{2 \cdot 5} : \frac{7}{5}

The solutions to the quadratic equation are:

p = 6, p = \frac{7}{5}

m^{2} - 8 m + 20 = 0

x, 3 x^{2} + 2 y^{2} = 0

2 x^{2} - 3 x - 3 = 2

9 (2 x + 8)^{2} + 41 = 42

- 2 x^{2} - 4 x + 1 = 0

What are the solutions to the equation 5p^2-37p=-42 ?
The solutions to the equation 5p^2-37p=-42 are p=6,p= 7/5
Find the zeros of 5p^2-37p=-42
The zeros of 5p^2-37p=-42 are p=6,p= 7/5