What are the solutions to the equation m^2-8m+20=0 ?

The solutions to the equation m^2-8m+20=0 are m=4+2i,m=4-2i

Find the zeros of m^2-8m+20=0

The zeros of m^2-8m+20=0 are m=4+2i,m=4-2i

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m^{2} - 8 m + 20 = 0

m = 4 + 2 i, m = 4 - 2 i

Solution steps

m^{2} - 8 m + 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 20 : 4 i

m_{1, 2} = \frac{- ( - 8 ) \pm 4 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 4 i}{2 \cdot 1}, m_{2} = \frac{- ( - 8 ) - 4 i}{2 \cdot 1}

m = \frac{- ( - 8 ) + 4 i}{2 \cdot 1} : 4 + 2 i

m = \frac{- ( - 8 ) - 4 i}{2 \cdot 1} : 4 - 2 i

The solutions to the quadratic equation are:

m = 4 + 2 i, m = 4 - 2 i

x, 3 x^{2} + 2 y^{2} = 0

2 x^{2} - 3 x - 3 = 2

9 (2 x + 8)^{2} + 41 = 42

- 2 x^{2} - 4 x + 1 = 0

x^{2} + 2 x + 4 = 2 x

What are the solutions to the equation m^2-8m+20=0 ?
The solutions to the equation m^2-8m+20=0 are m=4+2i,m=4-2i
Find the zeros of m^2-8m+20=0
The zeros of m^2-8m+20=0 are m=4+2i,m=4-2i