What are the solutions to the equation x^2+2x+4=2x ?

The solutions to the equation x^2+2x+4=2x are x=2i,x=-2i

Find the zeros of x^2+2x+4=2x

The zeros of x^2+2x+4=2x are x=2i,x=-2i

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x^{2} + 2 x + 4 = 2 x

x = 2 i, x = - 2 i

Solution steps

x^{2} + 2 x + 4 = 2 x

Move

4

to the right side

x^{2} + 2 x = 2 x - 4

Move

2 x

to the left side

x^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 4, x = - - 4

- 4 = 2 i

- - 4 = - 2 i

x = 2 i, x = - 2 i

7 x^{2} - 105 = 0

2 (3 x^{2} - 1) = - x

- 2 n^{2} = 14

2 x^{2} - 3 = 19

x^{2} - 16 x + 12 = 0

What are the solutions to the equation x^2+2x+4=2x ?
The solutions to the equation x^2+2x+4=2x are x=2i,x=-2i
Find the zeros of x^2+2x+4=2x
The zeros of x^2+2x+4=2x are x=2i,x=-2i