What are the solutions to the equation 2x^2-3=19 ?

The solutions to the equation 2x^2-3=19 are x=sqrt(11),x=-sqrt(11)

Find the zeros of 2x^2-3=19

The zeros of 2x^2-3=19 are x=sqrt(11),x=-sqrt(11)

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2 x^{2} - 3 = 19

x = 11, x = - 11

Solution steps

2 x^{2} - 3 = 19

Move

3

to the right side

2 x^{2} = 22

Divide both sides by

2

x^{2} = 11

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 11, x = - 11

x^{2} - 16 x + 12 = 0

x^{2} + 3 x - 10 = 0

- 4 x^{2} - 12 x + 5 = 0

s^{2} + 6 s + 12 = 0

- 5 x^{2} + 95 x + 100 = 0

What are the solutions to the equation 2x^2-3=19 ?
The solutions to the equation 2x^2-3=19 are x=sqrt(11),x=-sqrt(11)
Find the zeros of 2x^2-3=19
The zeros of 2x^2-3=19 are x=sqrt(11),x=-sqrt(11)