What are the solutions to the equation -4x^2-12x+5=0 ?

The solutions to the equation -4x^2-12x+5=0 are x=-(3+sqrt(14))/2 ,x=(sqrt(14)-3)/2

Find the zeros of -4x^2-12x+5=0

The zeros of -4x^2-12x+5=0 are x=-(3+sqrt(14))/2 ,x=(sqrt(14)-3)/2

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- 4 x^{2} - 12 x + 5 = 0

x = - \frac{3 + 14}{2}, x = \frac{14 - 3}{2}

Solution steps

- 4 x^{2} - 12 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 4 ) \cdot 5}{2 ( - 4 )}

(- 12)^{2} - 4 (- 4) \cdot 5 = 414

x_{1, 2} = \frac{- ( - 12 ) \pm 4 14}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 14}{2 ( - 4 )}, x_{2} = \frac{- ( - 12 ) - 4 14}{2 ( - 4 )}

x = \frac{- ( - 12 ) + 4 14}{2 ( - 4 )} : - \frac{3 + 14}{2}

x = \frac{- ( - 12 ) - 4 14}{2 ( - 4 )} : \frac{14 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 14}{2}, x = \frac{14 - 3}{2}

s^{2} + 6 s + 12 = 0

- 5 x^{2} + 95 x + 100 = 0

a x^{2} = 4 x - x^{2}

x^{2} - n^{2} x + 2 n = 0

4 x^{2} - 2 x + 5 = 0

What are the solutions to the equation -4x^2-12x+5=0 ?
The solutions to the equation -4x^2-12x+5=0 are x=-(3+sqrt(14))/2 ,x=(sqrt(14)-3)/2
Find the zeros of -4x^2-12x+5=0
The zeros of -4x^2-12x+5=0 are x=-(3+sqrt(14))/2 ,x=(sqrt(14)-3)/2