What are the solutions to the equation 5x^2-7x=3 ?

The solutions to the equation 5x^2-7x=3 are x=(7+sqrt(109))/(10),x=(7-sqrt(109))/(10)

Find the zeros of 5x^2-7x=3

The zeros of 5x^2-7x=3 are x=(7+sqrt(109))/(10),x=(7-sqrt(109))/(10)

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5 x^{2} - 7 x = 3

x = \frac{7 + 109}{10}, x = \frac{7 - 109}{10}

Decimal Notation

x = 1.74403 \dots, x = - 0.34403 \dots

Solution steps

5 x^{2} - 7 x = 3

Move

3

to the left side

5 x^{2} - 7 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 3 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 3) = 109

x_{1, 2} = \frac{- ( - 7 ) \pm 109}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 109}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 109}{2 \cdot 5}

x = \frac{- ( - 7 ) + 109}{2 \cdot 5} : \frac{7 + 109}{10}

x = \frac{- ( - 7 ) - 109}{2 \cdot 5} : \frac{7 - 109}{10}

The solutions to the quadratic equation are:

x = \frac{7 + 109}{10}, x = \frac{7 - 109}{10}

5 x^{2} - 7 x = 6

x^{2} - 16 x + 29 = 0

x^{2} + 5 x + c

x^{2} = - 30

x^{2} - 16 x + 27 = 0

What are the solutions to the equation 5x^2-7x=3 ?
The solutions to the equation 5x^2-7x=3 are x=(7+sqrt(109))/(10),x=(7-sqrt(109))/(10)
Find the zeros of 5x^2-7x=3
The zeros of 5x^2-7x=3 are x=(7+sqrt(109))/(10),x=(7-sqrt(109))/(10)