What are the solutions to the equation 2t^2+9t-3=0 ?

The solutions to the equation 2t^2+9t-3=0 are t=(-9+sqrt(105))/4 ,t=(-9-sqrt(105))/4

Find the zeros of 2t^2+9t-3=0

The zeros of 2t^2+9t-3=0 are t=(-9+sqrt(105))/4 ,t=(-9-sqrt(105))/4

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2 t^{2} + 9 t - 3 = 0

t = \frac{- 9 + 105}{4}, t = \frac{- 9 - 105}{4}

Decimal Notation

t = 0.31173 \dots, t = - 4.81173 \dots

Solution steps

2 t^{2} + 9 t - 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

9^{2} - 4 \cdot 2 (- 3) = 105

t_{1, 2} = \frac{- 9 \pm 105}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- 9 + 105}{2 \cdot 2}, t_{2} = \frac{- 9 - 105}{2 \cdot 2}

t = \frac{- 9 + 105}{2 \cdot 2} : \frac{- 9 + 105}{4}

t = \frac{- 9 - 105}{2 \cdot 2} : \frac{- 9 - 105}{4}

The solutions to the quadratic equation are:

t = \frac{- 9 + 105}{4}, t = \frac{- 9 - 105}{4}

x^{2} + (x + 1)^{2} + (x + 2)^{2} = - 1

x^{2} - 12 x + 3 = 0

4 x^{2} - 28 x + 53 = 0

x^{2} + 4 x - 2

x^{2} + 5 + 6 = 0

What are the solutions to the equation 2t^2+9t-3=0 ?
The solutions to the equation 2t^2+9t-3=0 are t=(-9+sqrt(105))/4 ,t=(-9-sqrt(105))/4
Find the zeros of 2t^2+9t-3=0
The zeros of 2t^2+9t-3=0 are t=(-9+sqrt(105))/4 ,t=(-9-sqrt(105))/4