What are the solutions to the equation x^2-12x+3=0 ?

The solutions to the equation x^2-12x+3=0 are x=6+sqrt(33),x=6-sqrt(33)

Find the zeros of x^2-12x+3=0

The zeros of x^2-12x+3=0 are x=6+sqrt(33),x=6-sqrt(33)

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x^{2} - 12 x + 3 = 0

x = 6 + 33, x = 6 - 33

Decimal Notation

x = 11.74456 \dots, x = 0.25543 \dots

Solution steps

x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 3 = 233

x_{1, 2} = \frac{- ( - 12 ) \pm 2 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 33}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 33}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 33}{2 \cdot 1} : 6 + 33

x = \frac{- ( - 12 ) - 2 33}{2 \cdot 1} : 6 - 33

The solutions to the quadratic equation are:

x = 6 + 33, x = 6 - 33

4 x^{2} - 28 x + 53 = 0

x^{2} + 4 x - 2

x^{2} + 5 + 6 = 0

s^{2} + 2 s + 3

4 x^{2} + 3 x - 3 = - 3 x

What are the solutions to the equation x^2-12x+3=0 ?
The solutions to the equation x^2-12x+3=0 are x=6+sqrt(33),x=6-sqrt(33)
Find the zeros of x^2-12x+3=0
The zeros of x^2-12x+3=0 are x=6+sqrt(33),x=6-sqrt(33)