What are the solutions to the equation 4x^2+3x-3=-3x ?

The solutions to the equation 4x^2+3x-3=-3x are x=(-3+sqrt(21))/4 ,x=-(3+sqrt(21))/4

Find the zeros of 4x^2+3x-3=-3x

The zeros of 4x^2+3x-3=-3x are x=(-3+sqrt(21))/4 ,x=-(3+sqrt(21))/4

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4 x^{2} + 3 x - 3 = - 3 x

x = \frac{- 3 + 21}{4}, x = - \frac{3 + 21}{4}

Solution steps

4 x^{2} + 3 x - 3 = - 3 x

Move

3 x

to the left side

4 x^{2} + 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 3) = 221

x_{1, 2} = \frac{- 6 \pm 2 21}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 21}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 21}{2 \cdot 4}

x = \frac{- 6 + 2 21}{2 \cdot 4} : \frac{- 3 + 21}{4}

x = \frac{- 6 - 2 21}{2 \cdot 4} : - \frac{3 + 21}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 21}{4}, x = - \frac{3 + 21}{4}

5 x^{2} = 17 x - 14

x (2 x - 1) = 3

r^{2} + r + 4 = 0

0 = - x^{2} - 6 x - 7

- 10 + 3 x^{2} = 0

What are the solutions to the equation 4x^2+3x-3=-3x ?
The solutions to the equation 4x^2+3x-3=-3x are x=(-3+sqrt(21))/4 ,x=-(3+sqrt(21))/4
Find the zeros of 4x^2+3x-3=-3x
The zeros of 4x^2+3x-3=-3x are x=(-3+sqrt(21))/4 ,x=-(3+sqrt(21))/4