What are the solutions to the equation x(2x-1)=3 ?

The solutions to the equation x(2x-1)=3 are x= 3/2 ,x=-1

Find the zeros of x(2x-1)=3

The zeros of x(2x-1)=3 are x= 3/2 ,x=-1

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x (2 x - 1) = 3

x = \frac{3}{2}, x = - 1

Solution steps

x (2 x - 1) = 3

Expand

x (2 x - 1) : 2 x^{2} - x

2 x^{2} - x = 3

Move

3

to the left side

2 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 3) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 2}

x = \frac{- ( - 1 ) + 5}{2 \cdot 2} : \frac{3}{2}

x = \frac{- ( - 1 ) - 5}{2 \cdot 2} : - 1

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 1

r^{2} + r + 4 = 0

0 = - x^{2} - 6 x - 7

- 10 + 3 x^{2} = 0

80 + y^{2} = 81

- x^{2} - 3 x - 4 = 0

What are the solutions to the equation x(2x-1)=3 ?
The solutions to the equation x(2x-1)=3 are x= 3/2 ,x=-1
Find the zeros of x(2x-1)=3
The zeros of x(2x-1)=3 are x= 3/2 ,x=-1