What are the solutions to the equation 2x^2=25 ?

The solutions to the equation 2x^2=25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))

Find the zeros of 2x^2=25

The zeros of 2x^2=25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} = 25

x = \frac{5}{2}, x = - \frac{5}{2}

Solution steps

2 x^{2} = 25

Divide both sides by

2

x^{2} = \frac{25}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{2}, x = - \frac{25}{2}

\frac{25}{2} = \frac{5}{2}

- \frac{25}{2} = - \frac{5}{2}

x = \frac{5}{2}, x = - \frac{5}{2}

2 x^{2} = 48

2 x^{2} = 80

7 x^{2} + 3 x - 4 = 0

15 x^{2} - 135 = 0

12 x^{2} + 2 x - 2 = 0

What are the solutions to the equation 2x^2=25 ?
The solutions to the equation 2x^2=25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))
Find the zeros of 2x^2=25
The zeros of 2x^2=25 are x= 5/(sqrt(2)),x=-5/(sqrt(2))