What are the solutions to the equation -8x^2+14x=0 ?

The solutions to the equation -8x^2+14x=0 are x=0,x= 7/4

Find the zeros of -8x^2+14x=0

The zeros of -8x^2+14x=0 are x=0,x= 7/4

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- 8 x^{2} + 14 x = 0

x = 0, x = \frac{7}{4}

Solution steps

- 8 x^{2} + 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

1 4^{2} - 4 (- 8) \cdot 0 = 14

x_{1, 2} = \frac{- 14 \pm 14}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 14 + 14}{2 ( - 8 )}, x_{2} = \frac{- 14 - 14}{2 ( - 8 )}

x = \frac{- 14 + 14}{2 ( - 8 )} : 0

x = \frac{- 14 - 14}{2 ( - 8 )} : \frac{7}{4}

The solutions to the quadratic equation are:

x = 0, x = \frac{7}{4}

6 x^{2} - 6 x + 12 = 0

3 x^{2} - 8 x - 35 = 0

- 4 x^{2} + 4 x + 3

(x + 3) (x + 2) = 0

\frac{2}{5} x^{2} = 0

What are the solutions to the equation -8x^2+14x=0 ?
The solutions to the equation -8x^2+14x=0 are x=0,x= 7/4
Find the zeros of -8x^2+14x=0
The zeros of -8x^2+14x=0 are x=0,x= 7/4