What are the solutions to the equation (x+3)(x+2)=0 ?

The solutions to the equation (x+3)(x+2)=0 are x=-3,x=-2

Find the zeros of (x+3)(x+2)=0

The zeros of (x+3)(x+2)=0 are x=-3,x=-2

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(x + 3) (x + 2) = 0

x = - 3, x = - 2

Solution steps

(x + 3) (x + 2) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x + 2 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x + 2 = 0 : x = - 2

The solutions to the quadratic equation are:

x = - 3, x = - 2

\frac{2}{5} x^{2} = 0

3 x^{2} + 6 x - 15 = 0

x^{2} + 12 x + 8 = - 5

4 x^{2} + 22 x + 30 = 0

x, z = x^{2} y^{3}

What are the solutions to the equation (x+3)(x+2)=0 ?
The solutions to the equation (x+3)(x+2)=0 are x=-3,x=-2
Find the zeros of (x+3)(x+2)=0
The zeros of (x+3)(x+2)=0 are x=-3,x=-2