What are the solutions to the equation x^2-23x+90=0 ?

The solutions to the equation x^2-23x+90=0 are x=18,x=5

Find the zeros of x^2-23x+90=0

The zeros of x^2-23x+90=0 are x=18,x=5

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x^{2} - 23 x + 90 = 0

x = 18, x = 5

Solution steps

x^{2} - 23 x + 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 1 \cdot 90}{2 \cdot 1}

(- 23)^{2} - 4 \cdot 1 \cdot 90 = 13

x_{1, 2} = \frac{- ( - 23 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 23 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 23 ) - 13}{2 \cdot 1}

x = \frac{- ( - 23 ) + 13}{2 \cdot 1} : 18

x = \frac{- ( - 23 ) - 13}{2 \cdot 1} : 5

The solutions to the quadratic equation are:

x = 18, x = 5

(x - 6)^{2} = - 36

x^{2} = (x - 1)^{2} + (x - 8)^{2}

4^{2} + 7^{2} = n^{2}

2 x^{2} - 4 x + c^{2} - 2 c - 3 = 0

x^{2} + 6 x - 24 = 4 x - x^{2}

What are the solutions to the equation x^2-23x+90=0 ?
The solutions to the equation x^2-23x+90=0 are x=18,x=5
Find the zeros of x^2-23x+90=0
The zeros of x^2-23x+90=0 are x=18,x=5