What are the solutions to the equation 4^2+7^2=n^2 ?

The solutions to the equation 4^2+7^2=n^2 are n=sqrt(65),n=-sqrt(65)

Find the zeros of 4^2+7^2=n^2

The zeros of 4^2+7^2=n^2 are n=sqrt(65),n=-sqrt(65)

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4^{2} + 7^{2} = n^{2}

n = 65, n = - 65

Decimal Notation

n = 8.06225 \dots, n = - 8.06225 \dots

Solution steps

4^{2} + 7^{2} = n^{2}

Switch sides

n^{2} = 4^{2} + 7^{2}

Simplify

4^{2} + 7^{2} : 65

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 65, n = - 65

2 x^{2} - 4 x + c^{2} - 2 c - 3 = 0

x^{2} + 6 x - 24 = 4 x - x^{2}

0 = x^{2} - 6 x + 12

x^{2} + 45 x + 600 = 0

3 x^{2} + 18 x + 13 = - 2

What are the solutions to the equation 4^2+7^2=n^2 ?
The solutions to the equation 4^2+7^2=n^2 are n=sqrt(65),n=-sqrt(65)
Find the zeros of 4^2+7^2=n^2
The zeros of 4^2+7^2=n^2 are n=sqrt(65),n=-sqrt(65)