What are the solutions to the equation 0=x^2-6x+12 ?

The solutions to the equation 0=x^2-6x+12 are x=3+sqrt(3)i,x=3-sqrt(3)i

Find the zeros of 0=x^2-6x+12

The zeros of 0=x^2-6x+12 are x=3+sqrt(3)i,x=3-sqrt(3)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - 6 x + 12

x = 3 + 3 i, x = 3 - 3 i

Solution steps

0 = x^{2} - 6 x + 12

Switch sides

x^{2} - 6 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 12 : 23 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1} : 3 + 3 i

x = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1} : 3 - 3 i

The solutions to the quadratic equation are:

x = 3 + 3 i, x = 3 - 3 i

x^{2} + 45 x + 600 = 0

3 x^{2} + 18 x + 13 = - 2

3 x^{2} = - 27

(x + 7) (x - 7) = 0

5 c^{2} + 12 c + 6 = 0

What are the solutions to the equation 0=x^2-6x+12 ?
The solutions to the equation 0=x^2-6x+12 are x=3+sqrt(3)i,x=3-sqrt(3)i
Find the zeros of 0=x^2-6x+12
The zeros of 0=x^2-6x+12 are x=3+sqrt(3)i,x=3-sqrt(3)i