What are the solutions to the equation 5c^2+12c+6=0 ?

The solutions to the equation 5c^2+12c+6=0 are c=(-6+sqrt(6))/5 ,c=-(6+sqrt(6))/5

Find the zeros of 5c^2+12c+6=0

The zeros of 5c^2+12c+6=0 are c=(-6+sqrt(6))/5 ,c=-(6+sqrt(6))/5

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5 c^{2} + 12 c + 6 = 0

c = \frac{- 6 + 6}{5}, c = - \frac{6 + 6}{5}

Decimal Notation

c = - 0.71010 \dots, c = - 1.68989 \dots

Solution steps

5 c^{2} + 12 c + 6 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

1 2^{2} - 4 \cdot 5 \cdot 6 = 26

c_{1, 2} = \frac{- 12 \pm 2 6}{2 \cdot 5}

Separate the solutions

c_{1} = \frac{- 12 + 2 6}{2 \cdot 5}, c_{2} = \frac{- 12 - 2 6}{2 \cdot 5}

c = \frac{- 12 + 2 6}{2 \cdot 5} : \frac{- 6 + 6}{5}

c = \frac{- 12 - 2 6}{2 \cdot 5} : - \frac{6 + 6}{5}

The solutions to the quadratic equation are:

c = \frac{- 6 + 6}{5}, c = - \frac{6 + 6}{5}

9 x^{2} - 3 x = 2

9 x^{2} - 20 x = 0

(5 x - 12)^{2} - 1 = 8

x^{2} - 12 x - 3 = 0

x^{2} - 3 x = - 1

What are the solutions to the equation 5c^2+12c+6=0 ?
The solutions to the equation 5c^2+12c+6=0 are c=(-6+sqrt(6))/5 ,c=-(6+sqrt(6))/5
Find the zeros of 5c^2+12c+6=0
The zeros of 5c^2+12c+6=0 are c=(-6+sqrt(6))/5 ,c=-(6+sqrt(6))/5