What are the solutions to the equation 64x^2-4=0 ?

The solutions to the equation 64x^2-4=0 are x= 1/4 ,x=-1/4

Find the zeros of 64x^2-4=0

The zeros of 64x^2-4=0 are x= 1/4 ,x=-1/4

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64 x^{2} - 4 = 0

x = \frac{1}{4}, x = - \frac{1}{4}

Solution steps

64 x^{2} - 4 = 0

Move

4

to the right side

64 x^{2} = 4

Divide both sides by

64

x^{2} = \frac{1}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{16}, x = - \frac{1}{16}

\frac{1}{16} = \frac{1}{4}

- \frac{1}{16} = - \frac{1}{4}

x = \frac{1}{4}, x = - \frac{1}{4}

3 (x - 1)^{2} = - 27

- 3 x^{2} + x = 13

1.5 x^{2} + 24 = 0

x, z = x^{2} + 3 x y + y^{2}

1 7^{2} = x^{2} + 1 5^{2}

What are the solutions to the equation 64x^2-4=0 ?
The solutions to the equation 64x^2-4=0 are x= 1/4 ,x=-1/4
Find the zeros of 64x^2-4=0
The zeros of 64x^2-4=0 are x= 1/4 ,x=-1/4