What are the solutions to the equation -3x^2+x=13 ?

The solutions to the equation -3x^2+x=13 are x= 1/6-i(sqrt(155))/6 ,x= 1/6+i(sqrt(155))/6

Find the zeros of -3x^2+x=13

The zeros of -3x^2+x=13 are x= 1/6-i(sqrt(155))/6 ,x= 1/6+i(sqrt(155))/6

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- 3 x^{2} + x = 13

x = \frac{1}{6} - i \frac{155}{6}, x = \frac{1}{6} + i \frac{155}{6}

Solution steps

- 3 x^{2} + x = 13

Move

13

to the left side

- 3 x^{2} + x - 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 3 ) ( - 13 )}{2 ( - 3 )}

Simplify

1^{2} - 4 (- 3) (- 13) : 155 i

x_{1, 2} = \frac{- 1 \pm 155 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 1 + 155 i}{2 ( - 3 )}, x_{2} = \frac{- 1 - 155 i}{2 ( - 3 )}

x = \frac{- 1 + 155 i}{2 ( - 3 )} : \frac{1}{6} - i \frac{155}{6}

x = \frac{- 1 - 155 i}{2 ( - 3 )} : \frac{1}{6} + i \frac{155}{6}

The solutions to the quadratic equation are:

x = \frac{1}{6} - i \frac{155}{6}, x = \frac{1}{6} + i \frac{155}{6}

1.5 x^{2} + 24 = 0

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1 7^{2} = x^{2} + 1 5^{2}

3 x^{2} = 180

\frac{7}{4} x^{2} + 7 x + 3 = \frac{7}{16} x^{2} + \frac{7}{4} x + 3

What are the solutions to the equation -3x^2+x=13 ?
The solutions to the equation -3x^2+x=13 are x= 1/6-i(sqrt(155))/6 ,x= 1/6+i(sqrt(155))/6
Find the zeros of -3x^2+x=13
The zeros of -3x^2+x=13 are x= 1/6-i(sqrt(155))/6 ,x= 1/6+i(sqrt(155))/6