What are the solutions to the equation 1.5x^2+24=0 ?

The solutions to the equation 1.5x^2+24=0 are x=4i,x=-4i

Find the zeros of 1.5x^2+24=0

The zeros of 1.5x^2+24=0 are x=4i,x=-4i

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1.5 x^{2} + 24 = 0

x = 4 i, x = - 4 i

Solution steps

1.5 x^{2} + 24 = 0

Move

24

to the right side

1.5 x^{2} = - 24

Divide both sides by

1.5

x^{2} = - 16

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 16, x = - - 16

- 16 = 4 i

- - 16 = - 4 i

x = 4 i, x = - 4 i

x, z = x^{2} + 3 x y + y^{2}

1 7^{2} = x^{2} + 1 5^{2}

3 x^{2} = 180

\frac{7}{4} x^{2} + 7 x + 3 = \frac{7}{16} x^{2} + \frac{7}{4} x + 3

4 x^{2} + 25 = - 20 x

What are the solutions to the equation 1.5x^2+24=0 ?
The solutions to the equation 1.5x^2+24=0 are x=4i,x=-4i
Find the zeros of 1.5x^2+24=0
The zeros of 1.5x^2+24=0 are x=4i,x=-4i