What are the solutions to the equation -3x^2-12x=0 ?

The solutions to the equation -3x^2-12x=0 are x=-4,x=0

Find the zeros of -3x^2-12x=0

The zeros of -3x^2-12x=0 are x=-4,x=0

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- 3 x^{2} - 12 x = 0

x = - 4, x = 0

Solution steps

- 3 x^{2} - 12 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 3 ) \cdot 0}{2 ( - 3 )}

(- 12)^{2} - 4 (- 3) \cdot 0 = 12

x_{1, 2} = \frac{- ( - 12 ) \pm 12}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12}{2 ( - 3 )}, x_{2} = \frac{- ( - 12 ) - 12}{2 ( - 3 )}

x = \frac{- ( - 12 ) + 12}{2 ( - 3 )} : - 4

x = \frac{- ( - 12 ) - 12}{2 ( - 3 )} : 0

The solutions to the quadratic equation are:

x = - 4, x = 0

x, 3 x^{2} + y = 3 y^{2} + x

4 x^{2} + 32 x + 236 = - 8

(2 x - 3)^{2} = x + 2 (7 - x^{2})

x^{2} + 144 = 40 x

x^{2} + 11 x + 1

What are the solutions to the equation -3x^2-12x=0 ?
The solutions to the equation -3x^2-12x=0 are x=-4,x=0
Find the zeros of -3x^2-12x=0
The zeros of -3x^2-12x=0 are x=-4,x=0