What are the solutions to the equation x^2+144=40x ?

The solutions to the equation x^2+144=40x are x=36,x=4

Find the zeros of x^2+144=40x

The zeros of x^2+144=40x are x=36,x=4

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x^{2} + 144 = 40 x

x = 36, x = 4

Solution steps

x^{2} + 144 = 40 x

Move

40 x

to the left side

x^{2} + 144 - 40 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 40 x + 144 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 1 \cdot 144}{2 \cdot 1}

(- 40)^{2} - 4 \cdot 1 \cdot 144 = 32

x_{1, 2} = \frac{- ( - 40 ) \pm 32}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 32}{2 \cdot 1}, x_{2} = \frac{- ( - 40 ) - 32}{2 \cdot 1}

x = \frac{- ( - 40 ) + 32}{2 \cdot 1} : 36

x = \frac{- ( - 40 ) - 32}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 36, x = 4

x^{2} + 11 x + 1

2 x^{2} = 3 x + 5

3^{2} + y^{2} = 4

3^{2} + y^{2} = 9

- x^{2} + 3 x + 7 = 0

What are the solutions to the equation x^2+144=40x ?
The solutions to the equation x^2+144=40x are x=36,x=4
Find the zeros of x^2+144=40x
The zeros of x^2+144=40x are x=36,x=4