What are the solutions to the equation -x^2+3x+7=0 ?

The solutions to the equation -x^2+3x+7=0 are x=-(-3+sqrt(37))/2 ,x=(3+sqrt(37))/2

Find the zeros of -x^2+3x+7=0

The zeros of -x^2+3x+7=0 are x=-(-3+sqrt(37))/2 ,x=(3+sqrt(37))/2

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- x^{2} + 3 x + 7 = 0

x = - \frac{- 3 + 37}{2}, x = \frac{3 + 37}{2}

Solution steps

- x^{2} + 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

3^{2} - 4 (- 1) \cdot 7 = 37

x_{1, 2} = \frac{- 3 \pm 37}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 37}{2 ( - 1 )}, x_{2} = \frac{- 3 - 37}{2 ( - 1 )}

x = \frac{- 3 + 37}{2 ( - 1 )} : - \frac{- 3 + 37}{2}

x = \frac{- 3 - 37}{2 ( - 1 )} : \frac{3 + 37}{2}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 37}{2}, x = \frac{3 + 37}{2}

5 x^{2} + 3 x = 3

u^{2} = 100

n^{2} - 8 n - 12 = 0

x, x^{2} - 4 x y + 4 y^{2} + 55 y + 1 = 0

3 a x^{2} + 2 b x + 2 c = 0

What are the solutions to the equation -x^2+3x+7=0 ?
The solutions to the equation -x^2+3x+7=0 are x=-(-3+sqrt(37))/2 ,x=(3+sqrt(37))/2
Find the zeros of -x^2+3x+7=0
The zeros of -x^2+3x+7=0 are x=-(-3+sqrt(37))/2 ,x=(3+sqrt(37))/2