What are the solutions to the equation n^2-8n-12=0 ?

The solutions to the equation n^2-8n-12=0 are n=2(2+sqrt(7)),n=2(2-sqrt(7))

Find the zeros of n^2-8n-12=0

The zeros of n^2-8n-12=0 are n=2(2+sqrt(7)),n=2(2-sqrt(7))

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n^{2} - 8 n - 12 = 0

n = 2 (2 + 7), n = 2 (2 - 7)

Solution steps

n^{2} - 8 n - 12 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 12) = 47

n_{1, 2} = \frac{- ( - 8 ) \pm 4 7}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 8 ) + 4 7}{2 \cdot 1}, n_{2} = \frac{- ( - 8 ) - 4 7}{2 \cdot 1}

n = \frac{- ( - 8 ) + 4 7}{2 \cdot 1} : 2 (2 + 7)

n = \frac{- ( - 8 ) - 4 7}{2 \cdot 1} : 2 (2 - 7)

The solutions to the quadratic equation are:

n = 2 (2 + 7), n = 2 (2 - 7)

x, x^{2} - 4 x y + 4 y^{2} + 55 y + 1 = 0

3 a x^{2} + 2 b x + 2 c = 0

x, 3^{y} = x^{2}

lo g_{10} (4) (x + 2) - lo g_{10} (16) (x^{2} - 4) = 1

2^{2} + b^{2} = 6^{2}

What are the solutions to the equation n^2-8n-12=0 ?
The solutions to the equation n^2-8n-12=0 are n=2(2+sqrt(7)),n=2(2-sqrt(7))
Find the zeros of n^2-8n-12=0
The zeros of n^2-8n-12=0 are n=2(2+sqrt(7)),n=2(2-sqrt(7))