What are the solutions to the equation 2^2+b^2=6^2 ?

The solutions to the equation 2^2+b^2=6^2 are b=4sqrt(2),b=-4sqrt(2)

Find the zeros of 2^2+b^2=6^2

The zeros of 2^2+b^2=6^2 are b=4sqrt(2),b=-4sqrt(2)

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2^{2} + b^{2} = 6^{2}

b = 42, b = - 42

Decimal Notation

b = 5.65685 \dots, b = - 5.65685 \dots

Solution steps

2^{2} + b^{2} = 6^{2}

Move

2^{2}

to the right side

b^{2} = 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 32, b = - 32

32 = 42

- 32 = - 42

b = 42, b = - 42

x^{2} + 6 x - 280 = 0

x, x^{2} - 4 y^{2} + 9 z^{2} = 36

x^{2} + 2 a x - 35 a^{2} = 0

k^{2} - 4 k - 21 = 0

(x^{2} + 4 x + 4) = 0

What are the solutions to the equation 2^2+b^2=6^2 ?
The solutions to the equation 2^2+b^2=6^2 are b=4sqrt(2),b=-4sqrt(2)
Find the zeros of 2^2+b^2=6^2
The zeros of 2^2+b^2=6^2 are b=4sqrt(2),b=-4sqrt(2)