What are the solutions to the equation x^2+6x-280=0 ?

The solutions to the equation x^2+6x-280=0 are x=14,x=-20

Find the zeros of x^2+6x-280=0

The zeros of x^2+6x-280=0 are x=14,x=-20

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x^{2} + 6 x - 280 = 0

x = 14, x = - 20

Solution steps

x^{2} + 6 x - 280 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 280 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 280) = 34

x_{1, 2} = \frac{- 6 \pm 34}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 34}{2 \cdot 1}, x_{2} = \frac{- 6 - 34}{2 \cdot 1}

x = \frac{- 6 + 34}{2 \cdot 1} : 14

x = \frac{- 6 - 34}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

x = 14, x = - 20

x, x^{2} - 4 y^{2} + 9 z^{2} = 36

x^{2} + 2 a x - 35 a^{2} = 0

k^{2} - 4 k - 21 = 0

(x^{2} + 4 x + 4) = 0

lo g_{10} (3) x^{2} - lo g_{10} (3) = 2

What are the solutions to the equation x^2+6x-280=0 ?
The solutions to the equation x^2+6x-280=0 are x=14,x=-20
Find the zeros of x^2+6x-280=0
The zeros of x^2+6x-280=0 are x=14,x=-20