What are the solutions to the equation (x^2+4x+4)=0 ?

The solutions to the equation (x^2+4x+4)=0 are x=-2

Find the zeros of (x^2+4x+4)=0

The zeros of (x^2+4x+4)=0 are x=-2

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(x^{2} + 4 x + 4) = 0

x = - 2

Solution steps

(x^{2} + 4 x + 4) = 0

Refine

x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 4 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 1}

x = \frac{- 4}{2 \cdot 1}

\frac{- 4}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

lo g_{10} (3) x^{2} - lo g_{10} (3) = 2

8 x - x^{2}

x^{2} + 6 x - 17 = 0

b, m = 4 f b^{2} - g^{2}

x, x^{2} + y^{2} + 4 x - 6 y + 13 = 0

What are the solutions to the equation (x^2+4x+4)=0 ?
The solutions to the equation (x^2+4x+4)=0 are x=-2
Find the zeros of (x^2+4x+4)=0
The zeros of (x^2+4x+4)=0 are x=-2