What are the solutions to the equation x^2+6x-17=0 ?

The solutions to the equation x^2+6x-17=0 are x=-3+sqrt(26),x=-3-sqrt(26)

Find the zeros of x^2+6x-17=0

The zeros of x^2+6x-17=0 are x=-3+sqrt(26),x=-3-sqrt(26)

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x^{2} + 6 x - 17 = 0

x = - 3 + 26, x = - 3 - 26

Solution steps

x^{2} + 6 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 17) = 226

x_{1, 2} = \frac{- 6 \pm 2 26}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 26}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 26}{2 \cdot 1}

x = \frac{- 6 + 2 26}{2 \cdot 1} : - 3 + 26

x = \frac{- 6 - 2 26}{2 \cdot 1} : - 3 - 26

The solutions to the quadratic equation are:

x = - 3 + 26, x = - 3 - 26

b, m = 4 f b^{2} - g^{2}

x, x^{2} + y^{2} + 4 x - 6 y + 13 = 0

8 x^{2} + 16 x - 27 = 15

x^{2} - 14 x = - 47

x^{2} + 20 x + 20 = 0

What are the solutions to the equation x^2+6x-17=0 ?
The solutions to the equation x^2+6x-17=0 are x=-3+sqrt(26),x=-3-sqrt(26)
Find the zeros of x^2+6x-17=0
The zeros of x^2+6x-17=0 are x=-3+sqrt(26),x=-3-sqrt(26)